1.)2x(5x/2-2x/5)
2.)Solve for x: 2x+3y=81
3x-6y=-57
3.)Find the length of the diagonal, to the nearest tenth of an inch, of a rectangle piece of paper that measures 8 1/2 by 11 inches.
4.)Given triangle ABC with a right angle C. Side AB=30 and side BC=15. Find the measure of angle A.
2.)Solve for x: 2x+3y=81
3x-6y=-57
3.)Find the length of the diagonal, to the nearest tenth of an inch, of a rectangle piece of paper that measures 8 1/2 by 11 inches.
4.)Given triangle ABC with a right angle C. Side AB=30 and side BC=15. Find the measure of angle A.
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1) Well, for the first one, you're going to want to solve what's inside the parentheses first. This means finding the most common denominator (remember that?):
2x (5x/2 - 2x/5)
2x (25x/10 - 4x/10)
2x (21x/10)
Now you can multiply:
2x(21x/10)
42x^2/10
4.2x^2
2) To solve for 'x', all you need to apply is a little substitution:
2x+3y=81
3y=81-2x
y=27-2x/3
With this value for 'y' known, you can plug it into the other equation:
3x-6y=-57
3x-6(27-2x/3)=-57
3x-162+4x=-57
7x=105
x=15
3) For this, you apply the Pythagorean Theorem:
√(8.5^2 + 11^2) = diagonal
√(72.25 + 121) = diagonal
√193.25 = diagonal
13.9 = diagonal
4) For this, you need a calculator able to use the inverse-sine function (or you must be familiar with certain right-triangles):
sin^-1(BC/AB) = A
sin^-1(15/30) = A
sin^-1(.5) = A
30°=A
2x (5x/2 - 2x/5)
2x (25x/10 - 4x/10)
2x (21x/10)
Now you can multiply:
2x(21x/10)
42x^2/10
4.2x^2
2) To solve for 'x', all you need to apply is a little substitution:
2x+3y=81
3y=81-2x
y=27-2x/3
With this value for 'y' known, you can plug it into the other equation:
3x-6y=-57
3x-6(27-2x/3)=-57
3x-162+4x=-57
7x=105
x=15
3) For this, you apply the Pythagorean Theorem:
√(8.5^2 + 11^2) = diagonal
√(72.25 + 121) = diagonal
√193.25 = diagonal
13.9 = diagonal
4) For this, you need a calculator able to use the inverse-sine function (or you must be familiar with certain right-triangles):
sin^-1(BC/AB) = A
sin^-1(15/30) = A
sin^-1(.5) = A
30°=A
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Alright, alright. Just giving you a hard time, is all...
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1.)2x(5x/2-2x/5)
= 2x(5/2x-2/5x)
= 21/5x^2
2) Standard form: 2x+3y=81; 3x-6y=-57;
substitute/eliminate x = -3/2y+81/2
substitute/eliminate y = +17
Solution: x = 15; y = 17;
or (x, y) = (15, 17)
4.)Given triangle ABC with a right angle C. Side AB=30 and side BC=15. Find the measure of angle A.
SSA: Sine Law: Sin(A)/a = Sin(B)/b
sides: 30, 15, 25.9808
angles: 90°, 30°, 60° is a right scalene triangle
area: 194.8557 perimeter: 70.9808
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∠ A = 30°
= 2x(5/2x-2/5x)
= 21/5x^2
2) Standard form: 2x+3y=81; 3x-6y=-57;
substitute/eliminate x = -3/2y+81/2
substitute/eliminate y = +17
Solution: x = 15; y = 17;
or (x, y) = (15, 17)
4.)Given triangle ABC with a right angle C. Side AB=30 and side BC=15. Find the measure of angle A.
SSA: Sine Law: Sin(A)/a = Sin(B)/b
sides: 30, 15, 25.9808
angles: 90°, 30°, 60° is a right scalene triangle
area: 194.8557 perimeter: 70.9808
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∠ A = 30°
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1.) Perform the addition in parentheses, then multiply by the factor outside.
.. 2x(x(2.5-0.4)) = 2x(2.1x) = 4.2x^2
2.) Double the first equation and add it to the second.
.. 2(2x+3y) + (3x-6y) = 2(81) + (-57)
.. 7x = 105 ... (collect terms)
.. x = 15 ... (divide by 7)
Substitute this value into the first equation.
.. 2(15) + 3y = 81
.. 30 + 3y = 81
.. 3y = 51
.. y = 17
The solution to the system of equations is (x, y) = (15, 17).
3.) sqrt(8.5^2+11^2) = sqrt(72.25+121) = sqrt(193.25) ≈ 13.9
The diagonal is 13.9 inches.
4.) The Law of Sines is helpful.
.. sin(C)/AB = sin(A)/BC
.. sin(A) = (BC/AB)*sin(C)
Since angle C is 90 degrees, its sine is 1. The sine of A is 15/30 = 1/2. Angle A is arcsin(1/2) = 30°.
.. 2x(x(2.5-0.4)) = 2x(2.1x) = 4.2x^2
2.) Double the first equation and add it to the second.
.. 2(2x+3y) + (3x-6y) = 2(81) + (-57)
.. 7x = 105 ... (collect terms)
.. x = 15 ... (divide by 7)
Substitute this value into the first equation.
.. 2(15) + 3y = 81
.. 30 + 3y = 81
.. 3y = 51
.. y = 17
The solution to the system of equations is (x, y) = (15, 17).
3.) sqrt(8.5^2+11^2) = sqrt(72.25+121) = sqrt(193.25) ≈ 13.9
The diagonal is 13.9 inches.
4.) The Law of Sines is helpful.
.. sin(C)/AB = sin(A)/BC
.. sin(A) = (BC/AB)*sin(C)
Since angle C is 90 degrees, its sine is 1. The sine of A is 15/30 = 1/2. Angle A is arcsin(1/2) = 30°.