HARDY-WEINBERG HELP PLEASE?!
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HARDY-WEINBERG HELP PLEASE?!

[From: ] [author: ] [Date: 11-06-15] [Hit: ]
just square root 0.One you do that you can find frequency of S (P) allele by doing 1-whateveryougotforsquarerooting0.This is p^2 , because P^2 stands for the dominant homozygous genotype.We already know that q^2 = 0.To find out q we have to square root.......
You are studying a population of 100 people and discover that 26 of these people are ss for a genetic condition. Use the Hardy-Weinberg equation to figure out the frequencies of the S and s alleles. What are the frequencies of the SS, Ss, and ss genotypes?

And please show your steps as to how you got your answer

-
p^2+2pq+q^2

ss genotype:

26/100 = 0.26 >>>This is the frequency of ss genotype because q^2 just means frequency of recessive genotype, so you already know those who are recessive....then just divide by population number (100) =]

Oh, and for frequency of s ( q) allele, just square root 0.26
One you do that you can find frequency of S (P) allele by doing 1-whateveryougotforsquarerooting0.26 =]

For the SS genotype:

This is p^2 , because P^2 stands for the dominant homozygous genotype. P+Q always = 1
We already know that q^2 = 0.26
To find out q we have to square root.
Square root of 0.26 = 0.5099019514 (we now have q)
1- 0.5099019514 = 0.4900980486 (this is p!)
So, p^2 to find out dominant genotype....
0.4900980486^2 = 0.2401960972 (this is your SS genotype, viola!)

Now, 2pq of equation is for heterozygous condition Ss
We know what p and q is from previous calculations, so...
2 x 0.4900980486 x 0.5099019514 = 0.4998039027 (This is your Ss genotype frequency)

Now, I hope the stages are clear and that I haven't made any typo's! I think if you google hardy-weinberg problems it will come up with a nice site so that you can practise these types of questions. It will help. =]

EDIT: Forgot to give you frequency of alleles. I've told you how to work it out in the first section without the answer.
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