How I can solve this (thermal expansion)
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How I can solve this (thermal expansion)

[From: ] [author: ] [Date: 11-05-30] [Hit: ]
-Starting with the equation for thermal expansion,dT = dL/[L*(Ca - Cs)] = .01/[2.0(24E-6 - 11E-6)] = 384.6°C-Its amazing! I found this for you.......
A steel bar (2 meters) and an aluminium bar (1.99 meters) have the same temperature (0 ºC). If they are heated until they have the same length, what should be the temperature for that to happen?
- coefficient steel: 11x10⁻6
- coefficient aluminium; 24x10⁻6
I appreciate any help.

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Starting with the equation for thermal expansion, I solved for dT:

dT = dL/[L*(Ca - Cs)] = .01/[2.0(24E-6 - 11E-6)] = 384.6°C

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It's amazing! I found this for you. http://yourselect.info/414563/aluminium-bar

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L1=Lo_a + C_a*Lo_a*d_T
L2=Lo_s + C_s*Lo_s*d_T
L1=L2
d_T = (Lo_a-Lo_s)/(C_s*Lo_s - C_a*Lo_a)
d_T = 388.2 ºC
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keywords: solve,expansion,How,thermal,this,can,How I can solve this (thermal expansion)
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