Snell's law: refraction of light
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Snell's law: refraction of light

[From: ] [author: ] [Date: 11-05-27] [Hit: ]
I did 1.63sin36 = 1.but thats not right. How do I solve this?!-You have to apply Snells law twice,......
I can't get this question!

The drawing shows a rectangular block of glass (n=1.52) surrounded by liquid carbon disulfide (n=1.63). A ray of light is incident on the glass at point A with an angle of 36 degrees. At what angle of refraction does the ray leave the glass at point B?

I did 1.63sin36 = 1.52sinx
but that's not right. How do I solve this?!

-
You have to apply Snell's law twice, one time for each interface

carbon disulfide --> glass for point A
glass --> carbon disulfide for point B
1
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