I can't get this question!
The drawing shows a rectangular block of glass (n=1.52) surrounded by liquid carbon disulfide (n=1.63). A ray of light is incident on the glass at point A with an angle of 36 degrees. At what angle of refraction does the ray leave the glass at point B?
I did 1.63sin36 = 1.52sinx
but that's not right. How do I solve this?!
The drawing shows a rectangular block of glass (n=1.52) surrounded by liquid carbon disulfide (n=1.63). A ray of light is incident on the glass at point A with an angle of 36 degrees. At what angle of refraction does the ray leave the glass at point B?
I did 1.63sin36 = 1.52sinx
but that's not right. How do I solve this?!
-
You have to apply Snell's law twice, one time for each interface
carbon disulfide --> glass for point A
glass --> carbon disulfide for point B
carbon disulfide --> glass for point A
glass --> carbon disulfide for point B