Interval of [0,2pi) terms of pi
5tan^2-15=0
tan^2x=3
tanx=sqt3
This is as far as ive got please help-tan^2x=3
=> tanx = +/- sqrt(3)
x = pi/3, 2pi/3, 4pi/3, 5pi/3
16x^4 -81
x^4-10x^2 + 25
i need to find the zeros, this kind of factoring includes imaginary number i-x^2 -8x +17
= (x^2 -8x +16) + 17-16
= (x-4)^2 + 1
= (x-4)^2 - i^2
= (x -4 -i) (x -4 +i)
so x = 4
1. The length of a rectangular boat storage shed must be 4 meters more than the width, and the perimeter must be at least 120 meters. What is the range of values for the width?
a. at least28 meters
Algebra. (:-Bring the 3 over -> 2t^2-5t-3=0
Now factor:
(2t+1)(t-3)->if you times it back out it turns to be:2t^2-6t+t-3->2t^2-5t-3=0
t=(-1/2) and 3-2t^2 - 5t = 3
2t^2 -5t -3 = 0
(2t +1)(t -3) = 0
5π/12 = π/6 + π/4 (another way to write it)
Use the angle addition formula for sine:
sin (a + b) = sin a * cosb + cos a * sin b
Substituting in a = π/6 and b = π/4
sin (π/6 + π/4)=
sin π/6 * cos
16) Subtract and simplify if possible. 76 11/18 - 60PLEASE explain if possible tx.-76 11/18 - 60
= 16 11/18-Given: 76 11/18 - 60
We need to first make the improper fraction into a proper fraction.
The logarithm base 10 of x is the exponent of 10 needed to produce x.
log10x = c means that where 10^c = x where x > 0
Logarithms base 10 are called common logarithms and log10x is written as log x.
I think the square root over the 15 is over the whole equation (i think).
ANSWER: -10√3 + 12√10
I dont know how they got the answer. Can someone please show me the answer?-1√15(-2√5 + 4√6)
1√15(-2√
sin^2x / 1 - cosx = 1 + cosx
Have no idea how to get the other side and tried multiple things!
I am confused!-sin^2/(1 - cos) = 1 + cos
(1 + cos)sin^2/((1 + cos)(s - cos)) = 1 + cos
sin^2(1 + cos)/
to solve ignore the sqrt and focus on sqrt(3) and 9.
since sqrt(3)*sqrt(3)*3 = 9 then sqrt(3)^4 = 9 (hope you follow my logic) and so:
sqrt(3)^(x+1) = sqrt(3)^4^(3x-1)
so x+1 = 4(3x-1)-->PEMDAS
x
Is the following geometric sequence 0.005+ 0.05+ 0.5+ ... converent, divergent, both or neither.How would you figure this out?-It is divergent since the common ratio is 10 which is >1 in absolute valu
Ideals of Z₂ x Z₄ must have order dividing 8.
Since (Z₂ x Z₄) / (Z₂ x Z₄) ≅ {0}, there is no maximal/prime ideal of order 8.
Order 4:
{0} x Z₄: Note that (Z₂ x Z₄) / ({0} x Z₄) ≅ Z₂ is a field/integ