I forgot how to resolve this kind of exersies, can anyone please resolve it with the prosses I just need to remember thanks!
Consider the ordered pair (1, 2) and the two equations in two unknowns:
M:
2x+y=9 find missing values x and y?1)x=-3so I do this
2(-3)+y=9
-6+y=9
y=9/-6
Buthere is the problem the computer won´t allow me to insert fractions.. so what can i do can I simplify this even more?
the standard form equation of a hyperbola is x^2/a^2-y^2/b^2=1.
PART I : what are the values of a and Bin the given equation?
A=------------------------------------…
B=--------------------------------
Fill in thevalues in the table below to give a legitimate probability distribution for the discrete random variable x , whose possible values are 2 ,3 , 4, 5, and 6.
I obviously cannot provide a table
Evaluate the integral using the given substitution?
the integral of 12s^3*ds / √(6-s^4)u= 6-s^4-∫12s³ds/√(6-s⁴)
We want to get everything in terms of u:
Since u = 6-s⁴, we can differentiate both side
Enter the quadratic equation in standard form. Use the caret (^) to enter exponents.For example enter x2 as x^2.
2x^2 - 10 - 3x = (x-2)^2 + 1-2x^2 -10 -3x = x^2 -4x + 4 +1
x^2 + x -15 = 0
I have a graph in front of me and it has one point (with a closed dot) at (-4, 2)then it goes down to (5,-4) with an arrow... how do i find the range from that???-The range is the set of y values.If t
Consider a t distribution with12 degrees of freedom. Compute P (-1.30
Consider a t distribution with8 degrees of freedom. Find the value ofc such that P(t > c) = 0.10 (the > has a line under it for
Im taking a summer class.. And need some help on some of the problems. Here are the problems listed below:
Find the precision for each measurement.
3.) 120 meters4.) 7 1/4 inches5.) 30.0 millimeters
y= x^2 + 7;
4
∫
2
y=-x^2+9;
5
∫
0
y=(x+1)^3;
3
∫
0
thanks !-Im not going to do your homework for you (thats what Wolfram|Alpha is for). If theres a problem youre having with integration techni
Express the following in the form ln x = ax + b and find the value of a and of b.
(a) xe^-x = 2.46
(b) (xe^x)^2 = 30e^-x
need the workings please-(a)
xe^-x = 2.46
ln (xe^-x) = ln (2.46), taking ln o
∫∫ xy/sqrt (x^2+y^2) dxdy
Limits of integration are both from 1 to 2.-Converting this directly to polar coordinates is painful!
Evaluating this directly:
∫(y = 1 to 2) ∫(x = 1 to 2) [xy / √(x^2+y^2)