Please help me !!!!
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answers:
M. say: An angle between 0 and 2π radians?
What is coterminal?
They end in different places.
My guess is π radians.
Not just π, but π radians.
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say: If it was f(1), how would you evaluate it? You'd plug a 1 in anywhere you saw an x, right? That's all you have to do here, except now you're using h(x)
f(h(x)) =>
h(x)^2 + 1
I'm presuming that h(x) = sqrt(x - 1) and not sqrt(x) - 1
(sqrt(x - 1))^2 + 1 =>
x - 1 + 1 =>
x
f(h(x)) = x
Which would mean that f(x) and h(x) are inverse functions to each other.
Now, if h(x) = sqrt(x) - 1, then it's a little different
f(h(x)) =>
(sqrt(x) - 1)^2 + 1 =>
x - 2 * sqrt(x) + 1 + 1 =>
x - 2 * sqrt(x) + 2
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TomV say: Add 2π to -5π repeatedly until the result is in the range 0 ≤ Θ < 2π
0 ≤ 2kπ - 5π < 2π
5π ≤ 2kπ < 7π
5/2 ≤ k < 7/2
2.5 ≤ k < 3.5
The only integer value of k in that range is 3. Hench the angle you are seeking is:
-5π + 6π = π
The angle between 0 and 2π that is coterminal with -5π is π (or 180°)
For this particular example, the answer is obvious. But the algorithm demonstrated above will yield the answer when the result may not be so obvious.
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Mike G say: π
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Mathmom say:
That would be π
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Bullwinkle say: ...just keep ADDING 2π until you reach the desired range !!
(- 5π) + 6π = π radians
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Kenny say: rgesrgs
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AmericanPatriot say: hi
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