How do you get from dy/dx = 12√x to 12x^1/2?

So here's the original question but I'm only clueless on one part:

The gradient of a curve is given by dy/dx = 12√x. The curve passes through the point (4, 50). Find the equation of the curve. [6]

In the mark scheme it says for the first part you get

∫12x^1/2 dx =8x^3/2

But how did they get "12x^1/2"

Thanks!!

√x = x^(1/2)

squaring gives, (√x)² = [x^(1/2)]²

so, (x^(1/2))(x^(1/2)) => x^(1/2 + 1/2) = x¹ => x

Note: x^(1/3) => ∛x and x^(1/4) => ∜x...e.t.c.

:)>

The nth-root of a number x is x^(1/n)
The square root of x is x^(1/2)

You're in Calculus?

The square root of x=x^1/2
since x^1/2*x^1/2=
x^(1/2+1/2)=x^1=x