Help on a level integration qns.?
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Help on a level integration qns.?

[From: ] [author: ] [Date: 14-03-09] [Hit: ]
C)∫ xcos2xdx limit from -pi/4 to 0 Please help me.i need working solutions to understand.these are my practice qns which I didnt manage to get the ans. Ans to the qns are: 2g)-120/pi • cospi/6((x/10) +1)+c H)0.5sin(x^2)+c3f)sin^(-1)(t-1)+c 6a)ln(2-3x)(x-(2/3))-x+c B)xsecx-ln|secx+tanx|+c D) (1/5)e^(2x) (2sinx-cosx)+c 7a)pi/18 C) (2-pi)/8-2g) ∫ 2 sin((3x+30)°) dx = ∫ 2 sin((3x+30)*π/180) dx ........
2. integrate each of the following with respect to x:
g)2sin(3x+30)^。
h)xcos(x^2)

3.find each of the following integrals:
f)∫ 1/(2t-t^2)^0.5 dt
6.find the following integrals:
a) ∫ ln(2-3x)dx
B) ∫ xsecxtanxdx
D) ∫ e^2x sinx dx
7. find the exact value of each of the following integrals:
A) ∫ dx/(4+9x^2) limit:from 0 to 2/(3^0.5).
C) ∫ xcos2xdx limit from -pi/4 to 0

Please help me.i need working solutions to understand.these are my practice qns which I didn't manage to get the ans.
Ans to the qns are:
2g)-120/pi • cospi/6((x/10) +1)+c
H)0.5sin(x^2)+c
3f)sin^(-1)(t-1)+c
6a)ln(2-3x)(x-(2/3))-x+c
B)xsecx-ln|secx+tanx|+c
D) (1/5)e^(2x) (2sinx-cosx)+c
7a)pi/18
C) (2-pi)/8

-
2g)

∫ 2 sin((3x+30)°) dx = ∫ 2 sin((3x+30)*π/180) dx
............................ = ∫ 2 sin(π/60(x+10)) dx

Use a substitution:
u = π/60(x+10)
du = π/60 dx
60/π du = dx

............................ = ∫ 2 sin(u) * 60/π du
............................ = ∫ 120/π sin(u) du
............................ = −120/π cos(u) + C
............................ = −120/π cos(π/60(x+10)) + C
............................ = −120/π cos(π/6(x/10+1)) + C

——————————————————————————————

2h)

u = x²
du = 2x dx

∫ x cos(x²) dx = ∫ 1/2 cos(x²) * 2x dx
.................. = ∫ 1/2 cos(u) du
.................. = 1/2 cos(u) + C
.................. = 1/2 cos(x²) + C

——————————————————————————————

3f)

∫ 1/√(2t−t²) dt = ∫ 1/√(1−(t²−2t+1)) dt
................... = ∫ 1/√(1−(t−1)²) dt

Use a substitution:
t − 1 = u
dt = du

................... = ∫ 1/√(1−u²) du
................... = sin⁻¹(u) + C
................... = sin⁻¹(t−1) + C

——————————————————————————————

6a)

Integrate by parts:
u = ln(2−3x) ............ dv = dx
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