How do I solve this Linear Equation please?
Favorites|Homepage
Subscriptions | sitemap
HOME > > How do I solve this Linear Equation please?

How do I solve this Linear Equation please?

[From: ] [author: ] [Date: 14-01-23] [Hit: ]
m = 30 / 0.Subbing,When h = 6 ft.,A 6-ft.weight would be 160 lbs.......
According to a study conducted in the U.S, a woman's optimal weight is 100 pounds when her height is 5 feet and 130 pounds when her height is 5.5 feet.

- Write a linear equation for a woman's optimal weight in pounds based on the number of inches of her height.

- What does the equation give as the optimal weight of a woman who is 6 feet tall?

-
h₁ = 5
w₁ = 100

h₂ = 5.5
w₂ = 130

m = (y₂ - y₁) / (x₂ - x₁)

Subbing known values,

m = (130 - 100) / (5.5 - 5)
m = 30 / 0.5
m = 60

b = w₁ - m(h₁)

Subbing,

b = 100 - 60(5)
b = 100 - 300
b = - 200

Weight-to-Height Function:

w(h) = 60h - 200
¯¯¯¯¯¯¯¯¯¯¯¯¯¯

When h = 6 ft.,

w(6) = 60(6) - 200
w(6) = 360 - 200
w(6) = 160

A 6-ft. tall woman's optimum
weight would be 160 lbs.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
 

-
Converting everything into inches because part of the problem says "based on the nubmer of inches of her height"

f(60) = 100
f(66) = 130

Slope = rise/run = 30/6 = 5
Point slope formula = y - 130 = 5(x - 66)
Simplifying gets you y = 5x - 200

For woman who is 6 feet (72 inches)
y = 5x - 200
y = 5(72) - 200
y = 160
1
keywords: solve,Linear,please,How,this,Equation,do,How do I solve this Linear Equation please?
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .