Solve probability problem...... help?
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Solve probability problem...... help?

[From: ] [author: ] [Date: 14-01-08] [Hit: ]
please help me guys, i really need to understand how so i could make a program for this...........
solve the probability of 2 dice , pack of deck of cards and 3 coins. if you draw simultaneously , what is the pprobability that 6 dots, 2 king & 3 heads will come out?

can anyone show me how to solve this thoroughly....
please help me guys, i really need to understand how so i could make a program for this.......

-
For the two dice, there are 5 ways of getting 6 dots,
namely (1,5), (2,4), (3,3), (4,2), (5,1), out of 6*6 = 36
possible outcomes, giving us a probability of 5/36.

For the deck of cards, the probability of the first card
drawn being a king is 4/52 = 1/13. Now that one king
has been drawn, there are 3 kings left out of 51 cards,
so the probability of drawing two kings without replacement
is (1/13)*(3/51) = (1/13)*(1/17) = 1/221.

Getting 3 heads has a probability of (1/2)^3 = 1/8.

The combined probability is then

(5/36)*(1/221)*(1/8) = 5/63648.

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assuming you role 2 die one time, toss 3 coins 1 time and select 2 cards from the deck:

# ways of getting a 6 on 2 die: you could have:
1,5
5,1
2,4
4,2
3,3
total ways (ie successes) = 5
total possible outcomes = 6*6 = 36
P(2 dots) = successes/possible outcomes = 5/36

P(2 kings) = (4/52)(3/51) = 12/2652

P(3 heads) = (1/2)^3 = 1/8

now we use multiplication rule to find P(all 3 outcomes):

(5/36)(12/2652)(1/8) = 60/763,776
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