Grade 9 exponents math help!
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Grade 9 exponents math help!

[From: ] [author: ] [Date: 13-11-05] [Hit: ]
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The question is (2a4b3) (-3ab) 3 (10a2b2) the numbers after the first numbers of each bracket are exponents and the letters are exponent. You guys probably already know that thanks! Full detail please!

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(2a⁴b³)(-3ab)³(10a²b²) = (2a⁴b³)(-3)³a³b³(10a²b²)
= (2a⁴b³)(-27)a³b³(10a²b²)
= -540a⁴⁺³⁺²b³⁺³⁺²
= -540a⁹b⁸

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assuming expression is

(2a^4b^3) times (-3ab)^3 times (10a^2b^2)

is the same as

(2a^4b^3) times (-3^1a^1b^1)^3 times (10a^2b^2)

law of exponents; to the power of a power, multiply the exponents

2a^4b^3 times [-3^(1times3) a^(1times3) b^(1times3)] times 10a^2b^2

2a^4b^3 times -3^3a^3b^3 times 10a^2b^2

law of exponents; multiply the bases, add the exponents

(2)(-3^3)(10) times a^(4+3+2) times b^(3+3+2)

20(-27) times a^9 times b^8

-540a^9b^8
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