Hi Sami
y = x² + 12
The first thing we would do is make x the subject of the equation
x² = y - 12
Lets take the square root of both sides of the equation
x = ±√(y - 12)
Its a ± because it can be a + square or a - square
Now we can switch x and y to get the inverse function
x = ±√(y - 12) becomes
y = ±√(x - 12)
So the inverse function is y = ±√(x - 12)
May your day be touched with sunshine.
y = x² + 12
The first thing we would do is make x the subject of the equation
x² = y - 12
Lets take the square root of both sides of the equation
x = ±√(y - 12)
Its a ± because it can be a + square or a - square
Now we can switch x and y to get the inverse function
x = ±√(y - 12) becomes
y = ±√(x - 12)
So the inverse function is y = ±√(x - 12)
May your day be touched with sunshine.
-
y=x^2 +12
swap y and x and solve for y
x = y² + 12
y² = x – 12
y = √(x – 12)
swap y and x and solve for y
x = y² + 12
y² = x – 12
y = √(x – 12)