An artificial satellite circling the Earth completes each orbit in 147 minutes...
Favorites|Homepage
Subscriptions | sitemap
HOME > > An artificial satellite circling the Earth completes each orbit in 147 minutes...

An artificial satellite circling the Earth completes each orbit in 147 minutes...

[From: ] [author: ] [Date: 13-11-05] [Hit: ]
......
An artificial satellite circling the Earth completes each orbit in 147 minutes. What is the value of g at the location of this satellite? The mass of the earth is 5.98 × 10^24 kg and the universal gravitational constant is 6.67259 × 10^−11 N m2/kg
Answer in units of m/s^2

-
g = (G*M) / [(G*M*(T^2)) / (4*(pi^2))]^(2/3)

I left out the derivation because you need to do your own homework. Here's to hoping I derived it correctly!
1
keywords: Earth,satellite,147,minutes,artificial,completes,An,in,orbit,circling,each,the,An artificial satellite circling the Earth completes each orbit in 147 minutes...
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .