Show that the slope of the line through the points.....
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Show that the slope of the line through the points.....

[From: ] [author: ] [Date: 13-11-05] [Hit: ]
M is the slope and - 3 /4 x is m so -3/4x is the slope!So both lines are perpendicular.......
Show that the slope of the line through the points (6,7) and (12,15) is perpendicular to the slope of the line given by the equation 4y+3x-5=0. Be sure to justify you answer.
Please walk me through to the answer, first get 10 points!

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First find the slope of the line with the points (6,7) and (12,15).
The slope formula is y2-y1 / x2-x1.
So substitute the points to get 15-7 / 12 - 6.
Simplify to get. 8 / 6 then 4 / 3.

If a line is perpendicular to another the its slope is the opposite reciprocal of the other's slope. So if aforementioned line has a slope of 4/3 then the line its perpendicular to should have a slope of
- 3 / 4. (Opposite reciprocal of a number is what is multiplied to the number to get -1. To find this just switch the numerator and denominator and change the sign)

So let's see if the equation shows a line with a slope of -3 / 4.
In the slope intercept form y=mx+b, m is the slope.
So solve for y by subtracting 4y from both sides to get 3x - 5 = -4y.
Then divide both sides by -4 to get y = -3 / 4 x - 5/4
M is the slope and - 3 /4 x is m so -3/4x is the slope!

So both lines are perpendicular.
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