An artificial satellite circling the Earth completes each orbit in 147 minutes. What is the value of g at the location of this satellite? The mass of the earth is 5.98 × 10^24 kg and the universal gravitational constant is 6.67259 × 10^−11 N m2/kg
Answer in units of m/s^2
I literally have no idea what im doing. All steps that are necessary to finding the answer would be great to have, thank you!
Answer in units of m/s^2
I literally have no idea what im doing. All steps that are necessary to finding the answer would be great to have, thank you!
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Combine the law of periods and the law of gravitation and you will be able to derive the answer I gave the last time you asked this question:
Law of periods (Kepler's 3rd Law):
(4*(pi^2))/(T^2) = (G*m)/(r^3)
Law of gravitation (Newton's Law of Universal Gravitation):
F = G*(m*M)/(r^2)
F = ma
F = mg
Recall my answer from last time:
g = (G*M) / [(G*M*(T^2)) / (4*(pi^2))]^(2/3)
I hope conceptually my answer helps, but I don't think it is in anyone's best interest for someone to do your homework for you. I really think you can do this now. I've given you the necessary tools. Give it a shot.
Law of periods (Kepler's 3rd Law):
(4*(pi^2))/(T^2) = (G*m)/(r^3)
Law of gravitation (Newton's Law of Universal Gravitation):
F = G*(m*M)/(r^2)
F = ma
F = mg
Recall my answer from last time:
g = (G*M) / [(G*M*(T^2)) / (4*(pi^2))]^(2/3)
I hope conceptually my answer helps, but I don't think it is in anyone's best interest for someone to do your homework for you. I really think you can do this now. I've given you the necessary tools. Give it a shot.