Short maths help,find the value of x,in it?
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Short maths help,find the value of x,in it?

[From: ] [author: ] [Date: 14-01-05] [Hit: ]
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(y+1)/(y-1)=(-10)^(2x)

-
The negative base makes it very difficult to actually solve--in fact impossible. If we assume that it is instead ((-10)²)^x = 100^x, (which is technically the same thing), the we get something solvable:

(y + 1)/(y - 1) = 100^x
--> take the natural log of both sides

ln((y + 1)/(y - 1) = ln(1000^x)
-->

x * ln(100) = ln((y + 1)/(y - 1))
-->

x = ln((y + 1) / (y - 1)) / ln(100)

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(y + 1) / (y - 1) = 100^x

log [ (y + 1) / (y - 1) ] = x log 100

log [ (y + 1) / (y - 1) ] = 2 x __________for log base 10

x = log [ (y + 1) / (y - 1) ] /2
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