Determine the value of the y-intercept:
2y + 3x - 12 = 0
I'm completely lost with how to complete this.
Help?
Thanks in advance!
2y + 3x - 12 = 0
I'm completely lost with how to complete this.
Help?
Thanks in advance!
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Hi April,
Rather than just give you the answer, I will TEACH you the process. Because you an give a man a fish and feed him for a day, or TEACH a man to fish and feed him for a lifetime!
so, here's the deal.... The y-intercept occurs when a graph crosses the y-axis. At that point, your x-value is zero. So you simply need to plug a zero in for x and solve for y. (to find the x intercept, you would plug in a zero for y and solve for x. finding the x intercept is also called finding the zeros of a function and is the most common thing you will do in hs algebra)
so, anyway, if you plug in zero for x, you have:
2y +3(0) -12 = 0
2y + 0 -12 =0
2y -12 = 0
2y = 12
y = 6.
So the y -intercept is at 6. Since x is zero at this point, the ordered pair is (0, 6)
I hope that helps!
Rather than just give you the answer, I will TEACH you the process. Because you an give a man a fish and feed him for a day, or TEACH a man to fish and feed him for a lifetime!
so, here's the deal.... The y-intercept occurs when a graph crosses the y-axis. At that point, your x-value is zero. So you simply need to plug a zero in for x and solve for y. (to find the x intercept, you would plug in a zero for y and solve for x. finding the x intercept is also called finding the zeros of a function and is the most common thing you will do in hs algebra)
so, anyway, if you plug in zero for x, you have:
2y +3(0) -12 = 0
2y + 0 -12 =0
2y -12 = 0
2y = 12
y = 6.
So the y -intercept is at 6. Since x is zero at this point, the ordered pair is (0, 6)
I hope that helps!
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you are welcome! have a happy math time!
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(0,6)