Add math question help

2lg(x^2(y))=lgx-lg(y+3)
express y in terms of x

2logx^2 + 2logy = logx - log(y + 3)

=> 2logy + log(y + 3) = logx - 2logx^2

=> logy^2 + log(y + 3) = logx - logx^4

so, log[y^2(y + 3)] = log(x/x^4)

=> y^2(y + 3) = 1/x^3

:)>

google it