Parametric Equation of a Curve
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Parametric Equation of a Curve

[From: ] [author: ] [Date: 13-02-16] [Hit: ]
x = sin(2pi/3) - sin(2*2/pi/3) = sin(2pi/3) - sin(4pi/3) = sqrt(3).y = (-1)... how do you think I got that value?Just do what I did for x.......
You are given the parametric equation of a curve and a value for the parameter t. Find the coordinates of the point on the curve corresponding to the given value of t.

x = sint-sin2t, y = cost+cos2t; t = 2pi/3

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This is just substitution:

x = sin(2pi/3) - sin(2*2/pi/3) = sin(2pi/3) - sin(4pi/3) = sqrt(3).

y = (-1)... how do you think I got that value? Just do what I did for x.
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keywords: Parametric,Curve,Equation,of,Parametric Equation of a Curve
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