You are given the parametric equation of a curve and a value for the parameter t. Find the coordinates of the point on the curve corresponding to the given value of t.
x = 3-t^2, y = 4+t^3; t = -1
x = 3-t^2, y = 4+t^3; t = -1
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Just plug int t = -1 to each equation to get the x and y coordinates:
x = 3 - (-1)^2 = 3 - 1 = 2
y = 4 + (-1)^3 = 4 - 1 = 3
x = 3 - (-1)^2 = 3 - 1 = 2
y = 4 + (-1)^3 = 4 - 1 = 3
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x=3-(-1)^2 = 2; y= 4+(-1)^3= 3
Point is (2,3) when t=-1
Point is (2,3) when t=-1