What is the solution this 2nd order non-homogenous ODE

y'' + 4y' = 4, initial conditions: y(0) = 1, y'(0) = 6

I dont understand how to find yp for this one because the first and 2nd derivative of a constant is 0. And 0 + 4(0) =/= 4. Please help! Thanks

aw, you should think about it more. Your ability would greatly increase if you thought of this on your own rather than me just tell you, but since you asked:

yes, derivatives of a constant are zero...but you need the left-hand side to be a constant so it matches the right. How do you do that? It means you need yp to be a function whose second derivative is zero, but whose first is a constant.

such a function is yp = Ax