Quick help with factoring and perimeter please

Hi, could someone help me with these and PLEASE guide me through the steps as to how you got the answer. Thank you!

1) Factor: 18x^2+67x-63

2) The length of a rectangular pool is 6 feet less than twice the width. If the perimeter of the pool is 126 feet, what are its dimensions?

Thanks again!

18x^2 +67x -63

COEFFICIENT OF x^2 = +18

( +18) ( -63) = -1134

FIND FACTORS OF -1134 WHICH ADD UP TO +67 ( COEFFICIENT OF x )

( +81) ( -14) = - 1134

18x^2 +81x -14x -63

9x ( 2x +9) -7( 2x +9)

( 9x- 7) ( 2x +9) ANSWER

2) Perimeter = 2 ( length + width)

126 = 2( length + width )

63 = length + width

Let the width be x ft

Length = 2x -6

Length + width = 2x -6 + x = 63

3x -6= 63

3x = 69

x = 23

Width = 23' Length = 40ft ANSWER