How to solve this using indefinite integral? Thanks
∫ [ 3/sqrt(t) ] dt
∫ [ 3/sqrt(t) ] dt
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3 is constant so it can be pulled out
3 ∫ (1/√t) dt
3 ∫ t^-1/2
3 * 2 * t^1/2
6t^1/2 + C
3 ∫ (1/√t) dt
3 ∫ t^-1/2
3 * 2 * t^1/2
6t^1/2 + C
-
3/sqrt(t)
= 3/t^0.5
= 3 t^-0.5
after integration
= 3t^(-0.5+1) / (-0.5+1)
= 6 t^0.5 + c
= 3/t^0.5
= 3 t^-0.5
after integration
= 3t^(-0.5+1) / (-0.5+1)
= 6 t^0.5 + c
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3t^-(1/2) dt