How do I solve these two: 5^(x-2) = 1/25 and ln(x^2-4) = ln21
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How do I solve these two: 5^(x-2) = 1/25 and ln(x^2-4) = ln21

[From: ] [author: ] [Date: 12-07-18] [Hit: ]
and thanks for the BA.Report Abuse -1.) 1/25 = 5^(-2), so the equation is 5^(x-2) = 5^(-2)--->x-2 = -2---> x = 0.2.) ln(x^2 - 4) = ln(21)--->x^2 - 4 = 21--->x^2 = 25--->x = 5 or x = -5.......
5^(x-2) = 1/25
5^(x-2) = 5^(-2)
x - 2 = -2
x = 0

ln(x^2-4) = ln21
x^2 = 25
x = -5 , 5

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You are welcome my good friend, and thanks for the BA.

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1.) 1/25 = 5^(-2), so the equation is 5^(x-2) = 5^(-2) ---> x-2 = -2 ---> x = 0.

2.) ln(x^2 - 4) = ln(21) ---> x^2 - 4 = 21 ---> x^2 = 25 ---> x = 5 or x = -5.
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keywords: and,two,these,solve,How,do,25,ln,21,How do I solve these two: 5^(x-2) = 1/25 and ln(x^2-4) = ln21
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