How many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill four positions on city council?
- I did it using permutations and set it up like this
city council
R R D I
9P2 5P1 2P1= 720
I'm not sure if I was supposed to use permutation though
- I did it using permutations and set it up like this
city council
R R D I
9P2 5P1 2P1= 720
I'm not sure if I was supposed to use permutation though
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when order matters its permutations, i dont think they said that the four positions are rank 1, rank 2 etc. then it should be combination my guess.. goodluck
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It's combinations, since it doesn't matter what order you select them in.
So, 9C2*5C1*2C1, if you're using a calculator.
So, 9C2*5C1*2C1, if you're using a calculator.