Help on calculus one question

Find slope of the tangent line to the graph of the given function at the given value of x

Y=x^4-5x^3+2 x=2

y = x^4 - 5x^3 + 2, x = 2

To find the slope of the tangent line, we first must find the derivative of this function. This is easily found via the power rule:

y' = 4x^3 - 15x^2

To find the slope of the tangent line, we simply plug in the x-value we were given, x = 2:

m = 4(2)^3 - 15(2)^2

Solve:

m = 4(8) - 15(4)

m = 32 - 60

m = -28

The slope of the line is m = -28.

find dy/dx and plug in x=2

dy/dx = 4x^3-15x^2, 4*8 - 15*4 = 32-60 = -28