I need a little help solving a math problem. I'm quite good at math, but I fail terribly in knowing which order I need to move the variables in this type of equation:
http://flic.kr/p/cn2YTq
I don't really care what the answer is, I just want to know how to get it. (What's the point of an answer, with no way of knowing how you came by it?)
Thank you!
http://flic.kr/p/cn2YTq
I don't really care what the answer is, I just want to know how to get it. (What's the point of an answer, with no way of knowing how you came by it?)
Thank you!
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Get a common denominator for the 2. So you have to multiply it by c, since it's on the side that says (1/c)
So 2 = 2c / c.
So then the right side becomes (1 - 2c)/c.
Then, just do a proportion.
a/b = (1 - 2c)/c
b(1 - 2c) = ac
b - 2bc = ac
b = 2bc + ac
Factor out the c
b = c(2b + a)
Divide by 2b + a
b/(2b + a) = c
I hope this information was very helpful.
So 2 = 2c / c.
So then the right side becomes (1 - 2c)/c.
Then, just do a proportion.
a/b = (1 - 2c)/c
b(1 - 2c) = ac
b - 2bc = ac
b = 2bc + ac
Factor out the c
b = c(2b + a)
Divide by 2b + a
b/(2b + a) = c
I hope this information was very helpful.
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Hey, look here!
To remedy the problem (which it did not seem to be) with ajedrez's method, I simply multiplied for a common denominator across the board. bc(a/b)=bc((1/c) - 2) --> ac = bc - 2bc. Same answer, slightly different way.
To remedy the problem (which it did not seem to be) with ajedrez's method, I simply multiplied for a common denominator across the board. bc(a/b)=bc((1/c) - 2) --> ac = bc - 2bc. Same answer, slightly different way.
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a/b=(1/c)-2---add 2 to both sides
(a/b)+2=1/c---multiply both sides by c and divide both sides by [(a/b)+2)] to isolate c
c=1/[(a/b)+2]
Basically just isolate the variable you're looking for, in this case c. Good luck.
(a/b)+2=1/c---multiply both sides by c and divide both sides by [(a/b)+2)] to isolate c
c=1/[(a/b)+2]
Basically just isolate the variable you're looking for, in this case c. Good luck.