Calorimetry help please
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Calorimetry help please

[From: ] [author: ] [Date: 12-06-28] [Hit: ]
so for 108 g it will be 25.454 X 108 = 2749.......
A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854 kj//Celcius. The temperature of the calorimeter increases from 23.06 Celcius to 30.19 Celcius.

A.) What is the heat of combustion per gram of quinone?


B.) What is the heat of combustion per mole of quinone?

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temperature change = 30.19 - 23.06 = 7.13 C

Q = 7.854 X 7.13 = 55.999 kj

so Q per gram = 55.999/2.2 = 25.454 kj/g

molecular mass of qunone = 108 g/mole

so as Q for 1 g is 25.454 kj

so for 108 g it will be 25.454 X 108 = 2749.032 kj/mole

feel free to ask any question
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