the number of bacteria present in a crop after T = hours is given by the following expression N (t) = No ^ t / 2 after how long the number of bacteria were increased from 1500 to 6000
-
You are given the original amount (No), which is 1500.
You are also given the new amount, n(t), which is 6000.
Plug them in and find 't:'
6000 = 1500^(t/2)
Take the log of both sides:
log 6000 = log 1500^(t/2)
Since log a^b = b log a, then:
log 6000 = (t/2) log 1500
log 6000 / log 1500 = t/2
(log 6000 / log 1500) * 2 = t
t = 2.379 hours
You are also given the new amount, n(t), which is 6000.
Plug them in and find 't:'
6000 = 1500^(t/2)
Take the log of both sides:
log 6000 = log 1500^(t/2)
Since log a^b = b log a, then:
log 6000 = (t/2) log 1500
log 6000 / log 1500 = t/2
(log 6000 / log 1500) * 2 = t
t = 2.379 hours