Tan(sec4) and sin(2arcsin(3/5)

I'm reviewing for my final and I got these two problems

tan(sec4)

sin(2arcsin(3/5)

How can I solve this without a calculator?

the 1st you can't...did you mean arcsec 4 ?...if so then tan Θ = √15 / 4

{ as arccos (1/4) = Θ means a triangle with sides √15 , 1 , 4 }

2nd is from sin 2x = 2 sin x cos x , sin [ 2 arcsin (3/5) ] = 2 (3/5)(4/5)