I was wondering, if I can just use LHopitals rule? Thanks in advance
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Not directly.
However, lim(n→∞) (x+1)/(2x+1) = 1/2 (by L'Hopital's Rule or otherwise).
So, lim(n→∞) arcsin[(x+1)/(2x+1)] = arcsin(1/2) = π/6.
I hope this helps!
However, lim(n→∞) (x+1)/(2x+1) = 1/2 (by L'Hopital's Rule or otherwise).
So, lim(n→∞) arcsin[(x+1)/(2x+1)] = arcsin(1/2) = π/6.
I hope this helps!
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Thanks again* lol
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