Limit of arcsin((x+1)/(2x+1)), x->infinity
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Limit of arcsin((x+1)/(2x+1)), x->infinity

[From: ] [author: ] [Date: 12-04-25] [Hit: ]
Thanks in advance-Not directly.However, lim(n→∞) (x+1)/(2x+1) = 1/2 (by LHopitals Rule or otherwise).So, lim(n→∞) arcsin[(x+1)/(2x+1)] = arcsin(1/2) = π/6.I hope this helps!......
I was wondering, if I can just use LHopitals rule? Thanks in advance

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Not directly.

However, lim(n→∞) (x+1)/(2x+1) = 1/2 (by L'Hopital's Rule or otherwise).

So, lim(n→∞) arcsin[(x+1)/(2x+1)] = arcsin(1/2) = π/6.

I hope this helps!

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Thanks again* lol

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keywords: infinity,arcsin,gt,Limit,of,Limit of arcsin((x+1)/(2x+1)), x->infinity
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