URGENT: A solution is made, with concentrations of chemicals D, E, and F as given below...

The solution is then allowed to come to equilibrium at a particular temperature, according to the reaction below. Calculate Kc for this reaction if the equilibrium value of D is as given.

D + E ----> 4 F
Initial [D]: 0.174 M Initial [E]: 0.384 M Initial [F]: 0.00 M
Equilibrium [D]: 0.050 M

Kc= ?

D + E <-------> 4F

initially...
0.174 + 0.384 <------> 0

at equilibrium...
(0.174-x) + (0.384-x) <-------> 4x

given equilibrium cocn. of D = 0.05 M

so 0.174-x = 0.05
x = 0.174-0.05 = 0.124 M

so equilibrium conc. of F = 4x = 4 X 0.124 = 0.496 M
and equilibrium conc. of E = 0.384-x = 0.384 - 0.124 = 0.26 M

Kc = [F]^4 / [D] [E]

putting the values...
Kc = 0.496^4 / 0.26 X 0.05

Kc = 0.061 / 0.013 = 4.692

feel free to ask any questions