F(x) = x^2. [0,1] interval use a right sum using two rectangles of equal length.
I get delta x as 1/2 giving me 2 rectangles. I then did. (F(.5)+f(1))1/2 which gives me . 625 but I'm not sure if that's right.
Solve and show work,
Is this the correct way to do a right sum?
I get delta x as 1/2 giving me 2 rectangles. I then did. (F(.5)+f(1))1/2 which gives me . 625 but I'm not sure if that's right.
Solve and show work,
Is this the correct way to do a right sum?
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delta x= b-a / n so 1/2 is correct.
now for the intervals(0,1/2) (1/2,1) [notice how delta x is used, the intervals are 2 of equal length of dx]
The sub intervals are right endpoints as asked so (1/2) and (1).
The integral = dx* [(1/2)^2 + (1)^2] = .625 Which is correct with right endpoints.
The function is a standard parabola, drawing 2 rectangles with right endpoints means your integral will be an over-estimation of the actual integral. Try doing it with sub intervals as midpoints and you answer will be more accurate. Use left endpoints and it will be an underestimation. Use a calculator and it will be exact :)
now for the intervals(0,1/2) (1/2,1) [notice how delta x is used, the intervals are 2 of equal length of dx]
The sub intervals are right endpoints as asked so (1/2) and (1).
The integral = dx* [(1/2)^2 + (1)^2] = .625 Which is correct with right endpoints.
The function is a standard parabola, drawing 2 rectangles with right endpoints means your integral will be an over-estimation of the actual integral. Try doing it with sub intervals as midpoints and you answer will be more accurate. Use left endpoints and it will be an underestimation. Use a calculator and it will be exact :)