please show me how to find the inverse Laplace transform for F(s)=s/(s^2+9)
Thank you
Thank you
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Since L{cos(at)} = s/(s^2 + a^2), letting a = 3 yields
L^(-1) {s/(s^2 + 9)} = cos(3t).
I hope this helps!
L^(-1) {s/(s^2 + 9)} = cos(3t).
I hope this helps!