I need to find the concentration Pb 2+ of the mixed solutions:
-10ml of 0.010M Pb(NO3)3
-0ml of water
-10ml of 0.020M of KI
Please help :)
-10ml of 0.010M Pb(NO3)3
-0ml of water
-10ml of 0.020M of KI
Please help :)
-
Do you really mean 0 mL of water?
If yes, then add the two volumes together 10 ml + 10 ml is 20 ml, so you have doubled the total volume. The concentration of Pb, then, is cut in half:
(10 ml/20 ml) * 0.010 M = 0.0050 M [Pb+2]
If there is a volume to the added water, then the total volume is substituted into the above equation where the 20 ml is now.
If yes, then add the two volumes together 10 ml + 10 ml is 20 ml, so you have doubled the total volume. The concentration of Pb, then, is cut in half:
(10 ml/20 ml) * 0.010 M = 0.0050 M [Pb+2]
If there is a volume to the added water, then the total volume is substituted into the above equation where the 20 ml is now.