The coordinates of ΔABC are A(0,4), B(6,0), and C(0, 0). Find the area of ΔABC.

The coordinates of ΔABC are A(0,4), B(6,0), and C(0, 0). Find the area of ΔABC.

A=bh/2
b=6 (from B), h=4 (from A), both given A is the origin.
So A=...?

If you draw the triangle on a grid with the axes labeled, you will see that it is a right-triangle with
base = 6 units and height = 4 units.
Area = 1/2 * base * height = 1/2 * 6 * 4 = 12 square units.

The two sides AC and BC are along the axis, so a rt triangle is formed with legs of 4, and 6

the area is (1/2)(base)(height) = (1/2)(4)(6) = 12 units^2

The coordinates of ΔABC are A(0, 4), B(6, 0), and C(0, 0).
Find the area of ΔABC.
ΔABC is right triangle with base 6 and height 4.
A
= 1/2 x base x height
= 12 square units

The proposed triangle is a right one.
BC is the base = 6
AC is the height = 4

Therefore, the area is BC*AC/2 = 12 sq units