We didn't have enough time to go over it in class so I'm utterly loss and we have a test tomorrow!!! If I can just get someone to solve this one problem I'm good to go!
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y=10-2x
x^2+(10-2x)^2 = 25
x^2+100-40x+4x^2 = 25
5x^2-40x+75 = 0
5(x-5)(x-3)=0
Solutions occur at x=3 and 5
(3,4) and (5,0)
x^2+(10-2x)^2 = 25
x^2+100-40x+4x^2 = 25
5x^2-40x+75 = 0
5(x-5)(x-3)=0
Solutions occur at x=3 and 5
(3,4) and (5,0)
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(3, 4) and (5, 0). I graphed them and this is what I got.