The sum of the length and the width of a proposed feed lot is 1260 ft. Find the length and width if their ratio must be 5:2.
-
l:w = 5:2
l+w = 1260
5x+2x = 1260
7x=1260
x=180
l = 5x = 5*180 = 900
p= 2x = 2*180 = 360
l+w = 1260
5x+2x = 1260
7x=1260
x=180
l = 5x = 5*180 = 900
p= 2x = 2*180 = 360
-
Anyone explain this math problem please?
The sum of the length and the width of a proposed feed lot is 1260 ft. Find the length and width if their ratio must be 5:2.
--------------------------------------…
L + W = 1260
If their ratio is 5:2, then the length is 5/(5+2) x 1260,
or 900 ft; the width is 5/(5+2) x 1260, or 360 ft.
The sum of the length and the width of a proposed feed lot is 1260 ft. Find the length and width if their ratio must be 5:2.
--------------------------------------…
L + W = 1260
If their ratio is 5:2, then the length is 5/(5+2) x 1260,
or 900 ft; the width is 5/(5+2) x 1260, or 360 ft.