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disproportionation reactions?
redox
MnO4 2- --> MnO4 1- + MnO2 (acidic)
Mn in MnO4 2- = 6+
Mn in MnO2 = 4+
Mn in MnO4 1- = 7+
2(MnO4 2- --> MnO4 1- + 1e-) = 2MnO4 2- --> 2MnO4 1- + 2e-
MnO4 2- + 2e- + 4H+ --> MnO2 + 2H2O
combine
3MnO4 2- + 4H+ --> 2MnO4 1- + MnO2 + 2H2O
H2SO3 --> S + HSO4-
S in H2SO3 = 4+
S solid = 0
S in HSO4- = 6+
H2SO3 + 4e- + 4H+ --> S + 3H2O
2(H2SO3 + H2O --> HSO4- + 2e- + 3H+) = 2H2SO3 + 2H2O --> 2HSO4- + 4e- + 6H+
3H2SO3 --> S + H2O + 2HSO4- + 2H+
redox
MnO4 2- --> MnO4 1- + MnO2 (acidic)
Mn in MnO4 2- = 6+
Mn in MnO2 = 4+
Mn in MnO4 1- = 7+
2(MnO4 2- --> MnO4 1- + 1e-) = 2MnO4 2- --> 2MnO4 1- + 2e-
MnO4 2- + 2e- + 4H+ --> MnO2 + 2H2O
combine
3MnO4 2- + 4H+ --> 2MnO4 1- + MnO2 + 2H2O
H2SO3 --> S + HSO4-
S in H2SO3 = 4+
S solid = 0
S in HSO4- = 6+
H2SO3 + 4e- + 4H+ --> S + 3H2O
2(H2SO3 + H2O --> HSO4- + 2e- + 3H+) = 2H2SO3 + 2H2O --> 2HSO4- + 4e- + 6H+
3H2SO3 --> S + H2O + 2HSO4- + 2H+
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I didn't answer them... but I suggest you to read your book. :).