What is the equation of the line that passes through the points (-2, 5) and (-7,1)
f) y-5=4/5(x+2)
g) y-5=5/4(x+2)
h)y+5=4/5(x-2)
j) y=5=5/4(x-2)
If f(2) = 13 , which could be the equation for f(x)?
a) f(x) = x^2 + 8
b) f(x) = x + x^2
c) f(x) = 2x^3+5
d) f(x) = 3x^2+1
Thanks :)
f) y-5=4/5(x+2)
g) y-5=5/4(x+2)
h)y+5=4/5(x-2)
j) y=5=5/4(x-2)
If f(2) = 13 , which could be the equation for f(x)?
a) f(x) = x^2 + 8
b) f(x) = x + x^2
c) f(x) = 2x^3+5
d) f(x) = 3x^2+1
Thanks :)
-
F
D
D
-
Okay for the first one you need to find the slope.
Slope formula = y1 - y2 over x1 - x2
4 over 5 is the answer from using both of the ordered pairs.
use the slope point formula = y - y1 = m (x - x1)
y - 5 = 4/5 (x - -2)
F is the answer.
F(x) = 13
f(2) = 13
f(2) = (2)^2 + 8 = 12
not A
f(2) = 2 + 4 =8
Not B
f(2) = 2(8) + 5
Not C
f(2) = 3(4) + 1 = 13
D is the answer
F and D are the answers.
Slope formula = y1 - y2 over x1 - x2
4 over 5 is the answer from using both of the ordered pairs.
use the slope point formula = y - y1 = m (x - x1)
y - 5 = 4/5 (x - -2)
F is the answer.
F(x) = 13
f(2) = 13
f(2) = (2)^2 + 8 = 12
not A
f(2) = 2 + 4 =8
Not B
f(2) = 2(8) + 5
Not C
f(2) = 3(4) + 1 = 13
D is the answer
F and D are the answers.