how many grams of N2O5 are required to produce 46g of NO2?
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Supposing the reaction to be:
2 N2O5 → 4 NO2 + O2
(46 g NO2) / (46.00558 g NO2/mol) x (2/4) x (108.01059 g N2O5/mol) = 54 g N2O5
2 N2O5 → 4 NO2 + O2
(46 g NO2) / (46.00558 g NO2/mol) x (2/4) x (108.01059 g N2O5/mol) = 54 g N2O5