Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 4.6; σ = 1.6
P(3 ≤ x ≤ 6) = ?
this is how I worked it.
P (3 - 4.6 /1.6 ≤ X - 4.6/1.6 ≤ 6 - 4.6/1.6)
P (-1.16/1.6 ≤ Z ≤ 1.4/1.6 ) = P ( -1 ≤ Z ≤ 0.875 )
.8159-.1587 = 0.6572
μ = 4.6; σ = 1.6
P(3 ≤ x ≤ 6) = ?
this is how I worked it.
P (3 - 4.6 /1.6 ≤ X - 4.6/1.6 ≤ 6 - 4.6/1.6)
P (-1.16/1.6 ≤ Z ≤ 1.4/1.6 ) = P ( -1 ≤ Z ≤ 0.875 )
.8159-.1587 = 0.6572
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looks correct, except that when I look in the normal table for the prob. corresponding to .875,
I get about .8092 (so .8092-.1587=.6505)
I get about .8092 (so .8092-.1587=.6505)