A metal is added to 25.0 mL of water. What is the specific heat of the metal when 10.0 g of the metal increase the temperature of water by 5.0 Degrees Celsius and causes the temperature of the metal to go down to 116.2 degrees Celsius ?
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-qmct=qmct
Water:
m=25g
C=4.184
T=+5
=523 J
Metal:
q=-523
m=10
T= -116.2
-523 x 10 x -116.2 x C= 523
6.08E5 x C = 523
523/6.08E5=8.6E-4
Water:
m=25g
C=4.184
T=+5
=523 J
Metal:
q=-523
m=10
T= -116.2
-523 x 10 x -116.2 x C= 523
6.08E5 x C = 523
523/6.08E5=8.6E-4
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