A barefoot field-goal kicker imparts a speed
of 52 m/s to a football initially at rest.
If the football has a mass of 0.69 kg and the
time of contact with the ball is 0.027 s, what
is the force exerted by the ball on the kicker’s
foot?
Answer in units of N.
of 52 m/s to a football initially at rest.
If the football has a mass of 0.69 kg and the
time of contact with the ball is 0.027 s, what
is the force exerted by the ball on the kicker’s
foot?
Answer in units of N.
-
Force = change of momentum/time
the change of the momentum of the football is mv2 - mv1 = 0.69*52 kgm/s.
the time is 0.027 s
--> the average force is
F = m/v/s = 0.69*52/0.027 = 1328.89 N
OG
the change of the momentum of the football is mv2 - mv1 = 0.69*52 kgm/s.
the time is 0.027 s
--> the average force is
F = m/v/s = 0.69*52/0.027 = 1328.89 N
OG