Logs help any one plzzzz

solve the simultaneous equation

ln(3x-y) = 2ln6 - ln9 and e^2x/e^y = e


thank you :)

ln(3x-y) = 2ln6 - ln9

=> ln(3x-y) = ln6^2 - ln9

=> ln(3x-y) = ln(6^2/9)

=> 3x - y = 36/9 = 4

e^2x/e^y = e

=> e^(2x-y) = e

2x - y = 1 -- (1)

you have 3x - y = 4 -- (2)

(1) - (2) : 2x - 3x = 1 - 4

-x = -3

x = 3

plug in to (1)

2(3) - y = 1

6 - y = 1

y = 5

3x-y = 4 ......(1)
2x-y = 1 ......(2)
(1)-(2): x = 3, y = 2x-1 = 5