Trig help please !!!!

I am stuck, please help. 1/1-sinA - 1/1+sinA = 2TanA/CosA and. TanA + CosA/sinA = 1/CosAsinA. Thank you :)

Please use parentheses to express equations accurately:

1/(1−sinA) − 1/(1+sinA)
= (1+sinA)/((1−sinA)(1+sinA)) − (1−sinA)/((1−sinA)(1+sinA))
= ((1+sinA) − (1−sinA)) / (1 − sin²A)
= 2 sinA / cos²A
= 2 sinA/cosA * 1/cosA
= 2 tanA/cosA

tanA + cosA/sinA
= sinA/cosA + cosA/sinA
= sin²A/(sinA cosA) + cos²A/(sinA cosA)
= (sin²A + cos²A) / (sinA cosA)
= 1/(sinA cosA)

Mαthmφm