Help part b .http://oi41.tinypic.com/30rv505.jpg
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Help part b .http://oi41.tinypic.com/30rv505.jpg

[From: ] [author: ] [Date: 12-01-29] [Hit: ]
tinypic.com/30rv505.kq3/r^2 = 0.9e9*q3 / 9 = 0.q3 = 3.e-10 C = 0.......
Help part b .http://oi41.tinypic.com/30rv505.jpg

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A positive charge should be placed so that the it will oppose the field at point A

kq3/r^2 = 0.3
r = 3 m

9e9*q3 / 9 = 0.3

q3 = 3.e-10 C = 0.3 n C

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