I'm doing some revision for a maths exam, and I need to solve the inequality 6y≥y+10. Please could you explain a simple way to solve this (or as simple as it can get).
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Solve for y, subtract y to each side: 6y - y >= 10
Combine y: 5y >= 10
Divide 5 to each side: y >= 2
So y has to be greater than or equal to 2 to make this inequality true.
Combine y: 5y >= 10
Divide 5 to each side: y >= 2
So y has to be greater than or equal to 2 to make this inequality true.
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So 6y≥y+10, now since y is positive on the you have to subtract y from both parts; so it becomes 6y-y≥y-y+10, which is 5y≥10, since 5y means 5 times y, when you take the 5 over it becomes the opposite, a divide so: y≥10/5 which is y≥2.
Hope it helps!
Hope it helps!
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5y ≥ 10
y ≥ 2
y ≥ 2