On an unknown planet, a pendulum of length 1.5 m swings with a period of 3.3 s. What is the acceleration of gr
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On an unknown planet, a pendulum of length 1.5 m swings with a period of 3.3 s. What is the acceleration of gr

[From: ] [author: ] [Date: 12-01-07] [Hit: ]
5(1.904)^2=5.4378.Answer is D.......
A. 3.7 m/s²
B. 12.7 m/s²
C. 7.1 m/s²
D. 5.4 m/s²
E. 9.8 m/s²

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t=2pi/w
1.5=2pi/w
w=1.904

A=x*w^2
A=1.5(1.904)^2=5.4378.
Answer is D.
1
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